Question

the perimeter of a rectangular field of breadth 11 1/2 cm is 30 cm. find its length and area​

Answer 1

Pls mark as brainliest answer

Answer 2

Answer:-

$\sf{The \ length \ of \ the \ rectangle \ is \ \frac{7}{2} \ cm}$

$\sf{and \ it's \ area \ is \ 40.25 \ cm^{2}}$

Given:

• $\sf{For, \ rectangle}$
• $\sf{Breadth(b)=11\frac{1}{2}}$
• $\sf{Perimeter\ is \ 30 \ cm}$

To find:

• Length and area of the rectangle.

Solution:

$\sf{Breadth=11\frac{1}{2}=\frac{23}{2}}$

$\boxed{\sf{Perimeter \ of \ rectangle=2(length+breadth)}}$

$\sf{2(length+\frac{23}{2})=30}$

$\sf{\therefore{2\times \ Length+23=30}}$

$\sf{\therefore{2\times \ Length=30-23}}$

$\sf{\therefore{2\times \ Length=7}}$

$\sf{\therefore{Length=\frac{7}{2} \ cm}}$

$\boxed{\sf{Area \ of \ rectangle=Length\times \ Breadth}}$

$\sf{\therefore{Area \ of \ rectangle=\frac{7}{2}\times\frac{23}{2}}}$

$\sf{\therefore{Area \ of \ rectangle=\frac{161}{4}}}$

$\sf{\therefore{Area \ of \ rectangle=40.25 \ cm^{2}}}$

$\sf\purple{\tt{\therefore{The \ length \ of \ the \ rectangle \ is \ \frac{7}{2} \ cm}}}$

$\sf\purple{\tt{and \ it's \ area \ is \ 40.25 \ cm^{2}}}$