the perimeter of a rectangular garden is 36 feet and the area is 80 square feet. Find the dimensions of the garden. show your solution.
Answers
Answered by
3
Answer:
10 and 8
Step-by-step explanation:
P= 2(l+w)
36= 2(l+w)
18=l+w
w=18-l
----------------
A=lw
80= L(18-L)
80=18L-L^2
L^2-18L+80=0
(L-10)(L-8)
L=10; L=8
The dimensions are 10 and 8 feet
Answered by
8
Answer:
2(l+b)=36
l+b=36/2
l+b=18
l=18-b ...(1)
l×b=80
(18-b)×b=80
18b-b^2=80
b^2-18b+80=0
b^2-10b-8b+80=0
b(b-10)-8 (b-10)=0
(b-10)(b-8)=0
b=10,8
b=8feet or 10feet
l=18-b
l=18-8 or 18-10
l=10feet or 8feet.
Similar questions