Question

The perimeter of a rectangular garden is 400 m. If the length and breadth are in the ratio of 3:2 then find the area of the garden?

Answer 1

$\underline{\underline{\mathfrak{\red{Answer:-}}}}$

area of rectangle = 9600 sq.m.

$\underline{\underline{\mathfrak{\red{Explanation:-}}}}$

Given:

Perimeter of rectangle = 400m

Ratio of length and breadth = 3:2

To find:

Area of triangle

Solution:

Let,

The length of the rectangle (l)= "3x"

The breadth of the triangle (b)= "2x"

$\boxed{\pink{Perimeter\: of \: rectangle = 2(l+b)}}$

Therefore,

2(l+b) = 400

2(3x+2x) = 400

2(5x) = 400

10x = 400

x = $\dfrac{400}{10}$

x = 40

_____________________

length (l) = 3x

l = 3(40)

l = 120m

breadth (b) = 2x

b = 2(40)

b = 80m

_____________________

Now,

$\boxed{\pink{area\: of \: rectangle = l \times b}}$

area of rectangle

= 120 × 80

= 9600 sq.m.

Hence,

area of rectangle = 9600 sq.m.