The perimeter of a rectangular garden, whose
length is 10m more than its width, is
80m. Then the Area of the garden is
O 320 m
O 364 m2
420 m2
375 m
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Answered by
0
Answer:
the length is 10 more than the width => l = w + 10.... eq(1)
perimeter is 80 cm => 2l + 2w = 80cm...eq(2)
now substitute eq(1) in to eq(2)
2(w + 10) + 2w = 80
2w + 20 + 2w = 80
4w + 20 -20 = 80 -20
4w = 60
w = 15
l = w + 10 = 15 + 10 = 25
2*15 + 2*25 = 80
Answered by
1
the answer is given in the attachment above
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