Question

the perimeter of a rectangular paper of breadth 23/22cm is 30 cm, find the length of the paper.​

Answer 1

$\bf{ \underline{ \underline{Answer \: : }}}$

$⟹\mathrm{Perimeter} = 2(l + b) \\ \\⟹\mathrm{Perimeter} = 2l + 2b \\ \\ ⟹\mathrm{Perimeter} \: = 2l + 2 \times \frac{23}{22} \\ \\ ⟹30 \: cm = 2l + 2 \: cm \\ \\ ⟹ 30 \: cm - 2 \: cm = 2l \\ \\ ⟹28 \: cm = 2l \\ \\ ⟹ \frac{28 \: cm}{2} = l \\ \\ ⟹l = 14 \: cm$

$\large\bold\red{Answer~is \: 14 \: cm \: .} \\ \\ \mathrm{ mark \: as \: brainliest \: answer \: and} \\ \mathrm{plz \: follow \: me. \: }$

Answer 2

Perimeter of Paper=30 cm

Breadth of Paper =23/22 cm

We Know Perimeter of Rectangle=2(l+b)

Where

L=length

B=Breadth

$2(l + \frac{23}{22} ) = 30 \\ \\ 2l + \frac{46}{22} = 30 \\ \\ 2l = 30 - \frac{46}{22} \\ \\ 2l = \frac{30 \times 22 - 46}{22} \: \: (lcm = 22) \\ \\ 2l = \frac{660 - 46}{22} \\ \\ 2l = \frac{614}{22} \\ \\ l = \frac{614}{22 \times 2} \\ \\ l = \frac{614}{44} \\ \\ l = \frac{307}{22}$

Length=307/22 cm