Math, asked by sunnyemmanuel1146, 11 months ago

The perimeter of a rectangular plot of land whose length is(2x-5)and width (x-10) is 80m find the area of the plot





Answers

Answered by shekhawatpiyush476
5

Answer:

bro the answer is 4xcubic meter

Answered by shivani3155
6

Answer:

area of rectangle is 2375/9 m²

Step-by-step explanation:

length of rectangle = 2x - 5

width of rectangle = x - 10

perimeter of rectangle = 80

perimeter of rectangle = 2(l+b)

80 = 2([2x-5] + [x-10])

80 = 2(2x - 5 + x - 10)

80/2 = 3x - 15

40 = 3x - 15

40 + 15 = 3x

55 = 3x

55/3 = x

length = 2x - 5 = 2 × 55/3 - 5

= 110/3 - 5

= (110 - 15)/3

= 95/3m

width = x - 10 = 55/3 - 10

= (55 - 30)/3

= 25/3m

area of rectangle = l × b

= 95/3 × 25/3

= 2375/9 m²

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