Math, asked by abidhasan3126, 4 months ago

The perimeter of a rectangular room is 246 m. If the length is 3 m more than thrice its breadth. Find the length and breadth of the pool.​

Answers

Answered by manas7083
38

bts \: exo \\  \\ very \: good \: afternoon

Given:-

Perimeter = 246 m

Length is 3 metre more than 2x its breadth.

Solution

Let us assume breadth as x.

So, length is 3+2x

According to the question:-

Perimeter = 2(L+B)

L is length

B is breadth

=246=2(3+2x+x)

=246=2(3+3x)

=246=6+6x

=246-6=6x

=240=6x

x=240÷6

x=80m

LIFE GOES ON

Answered by MissEyre
204

\huge\mathfrak\green{Answer:}

Given:

  • We have been given that , Perimeter of a rectangular room is 246 m
  • Length is 3m more than thrice its breadth

To Find:

  • We have to find the length and Breadth of the Rectangle

Solution:

Let us assume :

  • Length of Rectangle = x
  • Breadth of Rectangle = y

\underline{\bf{According \: to \: the \: Question:}}

Length is 3m more than thrice it's Breadth

\leadsto{\bf{ x - 3y = 3 }}

\leadsto{\bf{ x = 3y + 3 }} ------------- (1)

We have also given Perimeter of Rectangle

Perimeter of Rectangle :

  • Perimeter of Rectangle is twice the sum of its Length and Breadth .
  • Mathematically can be written as

\boxed{\sf{\green{Perimeter = 2 \: ( Length + Breadth )}}}

\sf{}

Since Perimeter of Rectangle is 246 m

\leadsto{\bf{ Perimeter  = 246 }}

\leadsto{\bf{ 2 \: ( x + y ) = 246}}

Putting value of x , From Equation (1)

\leadsto{\bf{ 2 \: ( 3y + 3 + y ) = 246}}

\leadsto{\bf{ 2 \: ( 4y + 3 ) = 246}}

\leadsto{\bf{ 4y + 3 = 123 }}

\leadsto{\bf{ 4y = 120 }}

\leadsto{\boxed{\bf{ y = 30}}}

Putting y = 30 in Equation (1) , We get

\leadsto{\bf{ x = 3y + 3 }}

\leadsto{\bf{ x = 90 + 3}}

\leadsto{\boxed{\bf{ x = 93 }}}

\sf{}

\underline{\boxed{\sf{\green{Length \: of \: Rectangle = 93 m}}}}

\underline{\boxed{\sf{\green{Breadth \: of \: Rectangle = 30 m}}}}

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