Math, asked by labanyaravi911, 2 months ago

the perimeter of a rectangular sheet is 100cm. If the length is 35cm, find its breadth. Also find the area.​

Answers

Answered by yuvrajparmar52599
1

Answer:

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Answered by MasterDhruva
5

Given :-

Perimeter of a sheet :- 100 cm

Length of the sheet :- 35 cm

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To Find :-

The breadth and the area of the rectangle.

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How to do :-

Here, we are given with the perimetre and the length of the rectangular sheet. We are asked to find the breadth and the area of that sheet. So, first we should find the breadth as for finding area the breadth is also required. The formula is given while solving the problem. The simplified answer will be the breadth. To find the area also, the specific formula is given while solving the problems. By using those, we can find the answers. So, let's solve!!

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Solution :-

Breadth of the rectangle :-

{\tt \leadsto \underline{\boxed{\tt \dfrac{Perimetre}{2} - Length}}}

Substitute the values.

{\tt \leadsto \dfrac{100}{2} - 35}

Write the fraction in lowest form by using cancellation method.

{\tt \leadsto \cancel \dfrac{100}{2} - 35 = \dfrac{50}{1} - 35}

We can also write this fraction as numerical format.

{\tt \leadsto 50 - 35}

Now,subtract to get the value of breath.

{\tt \leadsto \pink{\underline{\boxed{\tt Breadth = 15 \: \: cm}}}}

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Now, we can find the area using the length and breadth.

Area of the rectangle :-

{\tt \leadsto \underline{\boxed{\tt Length \times Breadth}}}

Substitute the values.

{\tt \leadsto 35 \times 15}

By, multiplying we can get the value of area.

{\tt \leadsto \pink{\underline{\boxed{\tt {525 \: \: cm}^{2}}}}}

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Hence solved !!

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\dashrightarrow Some related formulas :-

\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\  \bigstar \:  \sf{{Length}_{(Rectangle)} = \dfrac{Perimeter}{2} - Breadth} \\ \\ \bigstar \:\sf{{Length}_{(Rectangle)} = \dfrac{Area}{Breadth}} \\  \\ \bigstar \:  \sf{{Breadth}_{(Rectangle)} = \dfrac{Area}{Length}} \\  \\ \bigstar \:  \sf{{Perimeter}_{(Rectangle)} = 2 \: (Length + Breadth)}\end{array}}

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