Question

The perimeter of a rectangular swimming pool 154 m. Its length is 2 m
more than twice its breadth. What are the length and the breadth of a pool?​

Answer 1

Answer:

Step-by-step explanation:

The perimeter of a rectangle is 2(l+b) = 154

l = 2 + 2b

Substituting,

2(2 + 2b + b) = 154

4 + 6b = 154

b = 25

l = 52

Thus, the length is 52 m and the breadth is 25 m.

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Length is 52 m and Breadth is 25 m.

$\mathfrak{\large{\underline{\underline{Explanation :- }}}}$

Given :

Perimeter of the Rectangle = 154 m

The Length is = 2m more than Twice of Breadth

To find :

The Length and Breadth of the Rectangle

Solution :

Consider the Breadth as x

Length = 2x + 2

★ We know that :

Perimeter = $\sf{2(length + breadth)}$

$\tt{\implies} \: 2(x + 2x + 2) = 154$

$\tt{\implies} \: 2x + 4x + 4 = 154$

$\tt{\implies} \: 6x = 154 - 4$

$\tt{\implies} \: 6x = 150$

$\tt{\implies} \: x = \dfrac{150}{6}$

$\tt{\implies} \: x = 25$

Value of 2x + 2

$\tt{\implies} \: 25 \times 2 + 2$

$\tt{\implies} \: 50+ 2$

$\tt{\implies} \:52$

$\therefore$ The Length is 52 m and Breadth is 25 m.

$\mathfrak{\large{\underline{\underline{Verification :-}}}}$

$\tt{\implies} \: 2(25 + 52) = 154$

$\tt{\implies} \:50 + 104= 154$

$\tt{\implies} \: 154 = 154$

$\therefore$ The Length is 52 m and Breadth is 25 m.