Question

the perimeter of a rectangular swimming pool is 154 . It's length is 2m more than twice its breadth if the length and breadth are doubled what will be the perimeter​

Answer 1

Step-by-step explanation:

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Answer 2

$\large \bf \red{ \underline { \green\clubs{Given:-}}}$

${Length = (2x + 2)m}$

$Perimeter = 154\:m$

$\large \bf \red{ \underline { \green \clubs{Solution:-}}}$

$Let \: the \: breadth \: = x \:$

$Length = (2x + 2)m$

$\blue{Perimeter = 2(l + b)}$

$154 = 2(2x + 2 + x)$

$154 = 2(3x + x)$

$154 = 6x + 4$

$6x = 154 - 4$

$x = \cancel\frac{150}{6}$

$x = 25$

$__________________________________$

$Breadth = x \\ \: \therefore{Breadth = 25 \: m}$

$Length = (2x + 2) \\ \: \therefore{Length = 52 \: m}$

$\large \blue{ \underline{ \pink{If \: we \: double \: the \: length \: and \: breadth}}}$

$Length = 52 \times 2 =104 \: m$

$Breadth = 25 \times 2 = 50 \: m$

$\large{ \blue{Perimeter = 2(l + b)}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2(104 + 50)$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 154$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =308 \: m$

$\blue {\therefore{Perimeter = 308 \: m}}$