Question

the perimeter of a rectrangular is 154m. its length is 2m more than twice its breadth. what are the length ang th3 breadth​

Answer 1

perimeter of rectangle=2(l+b)

take breadth as x

then length will be 2x+2

therefore

2(x+2x+2) =154

2(3x+2) =154

3x+2=77

3x=77-2=75

3x=75

x=75/3

x=25

therefore

breadth = 25

length = 2 * 25 + 2

= 50+2=52

Answer 2

Let the breadth of the rectangle be x m

Since is 2m more than the twice its breadth

Let the length be (2x + 2)m

Perimeter of the rectangle = 154 m

2(Length + Breadth) = 154 m

2(2x + 2 + x) = 154

3x + 2 = 154/2

3x + 2 = 77

3x = 77 - 2

3x = 75

x = 75/3

x = 25

So Breadth = x = 25 m

Length = 2x + 2 = 2(25) + 2 = 50 + 2 = 52m

Verification:

2(2x + 2 + x) = 154

2(52 +  25) = 154

2(77) = 154

154 = 154

LHS = RHS