The perimeter of a rhombis is 20 cm if one of its diagonal is 6 cm the find the other diagonal and the area of the rhombus
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hay mate here is ur ans
in rhombus has all 4 sides are equal
so each side =20/4=5cm
now the diagonals of rhombus bisect each other at 90 degrees
so 1/2*d2=root of (side²-(diagonal /2)²)
=new diagonal =2*(root of (5²-6/2²))=2*root of (25-9)=2*root of 16=2*4=8cm
now area=1/2*d1*d2=1/2*8*6=24cm²
hope it helps you frnd
in rhombus has all 4 sides are equal
so each side =20/4=5cm
now the diagonals of rhombus bisect each other at 90 degrees
so 1/2*d2=root of (side²-(diagonal /2)²)
=new diagonal =2*(root of (5²-6/2²))=2*root of (25-9)=2*root of 16=2*4=8cm
now area=1/2*d1*d2=1/2*8*6=24cm²
hope it helps you frnd
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