The perimeter of a rhombous is 100 cm. If one of its diagonals is 14 cm, then the area of the rhombous is
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allside are = in rhomboid
a+a+a+a=100cm
4a=100cm
a=25
diagonal bisects each other=14/2=7
if one side is 25cm
and another one is 7
by p.t.
H²=B²+P²
H=25
B=7
P=?
25²=7²+P²
625=49+p²
625-49=P²
576=P²
√576=P
24=P
a+a+a+a=100cm
4a=100cm
a=25
diagonal bisects each other=14/2=7
if one side is 25cm
and another one is 7
by p.t.
H²=B²+P²
H=25
B=7
P=?
25²=7²+P²
625=49+p²
625-49=P²
576=P²
√576=P
24=P
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