Question

The perimeter of a rhombus ABCD is 100 cm. If the length of the diagonal AC is 14 cm, find the
diagonal BD
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Answer 1

we know that.......... the diagonal of rhombus bisect each other at 90° equally

by pythagoras theorem......

In triangle DOC , WE HAVE AO =CO = 7 CM

DC^2=OC^2 + DO^2

25^2=7^2 +DO^2

DO^2 =(25+7 ) (25- 7)

= 32× 18

DO^2 = 576

SO, DO = UNDER ROOT 576

DO = under root 24×24

DO= 24CM

ACC.TO QUESTION

BD = 2 × DO

= 2 × 24

= 48 CM