The perimeter of a rhombus ABCD is 100cm.if the length of the diagonal AC is 14 cm, find the length of the diagonal BD
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Perimeter=100cm
side=25cm
By Pythagoras formula
25^2=(1/2AC)^2+(1/2BD)^2
625=7^2+1/4BD^2
625-49=1/4BD^2
576=1/4BD^2
576*4=BD^2
2304=BD^2
√2304=BD
48cm=BD
Hope, this helps you.
side=25cm
By Pythagoras formula
25^2=(1/2AC)^2+(1/2BD)^2
625=7^2+1/4BD^2
625-49=1/4BD^2
576=1/4BD^2
576*4=BD^2
2304=BD^2
√2304=BD
48cm=BD
Hope, this helps you.
pr16521:
Ok but I had made with another method ok thanks for helping me
your welcome
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