Question

The perimeter of a rhombus ABCD is 40 cm . Find the area of rhombus of its diagonals BD measures 12 cm.

Answer 1

Hey dear!!


Here is yr answer....


Given,

Diagonal BD of rhombus = 12cm

Perimeter of rhombus = 40cm

4s = 40

s = 40/4

s = 10cm


Now,

Divide the rhombus into four right angled triangles.

Such that, every triangle has a hypotrneuse of 10cm


12/2 = 6cm

Using pythagorus therom :

= √10² - 6²

= 8cm



Now,

8+8= 16cm (sum of the bases of two triangles = measure of d1)


Area of rhombus = 1/2 × d1 × d2

= 1/2 × 16 × 12

= 96cm²


Therefore, diagonal AC = 16cm and the area of rhombus = 96cm²


Hope it hlpz...

Answer 2

Answer:

ANSWER

R.E.F image

Side =

4

pperimete =10cm

10 2 −6 2 =x 2

x 2 =64⇒x=8

∴ other diagonal =2x=16cm

∴ Area =

21 d 1

d 2

= 21 ×16×12=16×6=96cm 2

solution