The perimeter of a rhombus ABCD is 60 cm.Find the area of the rhombus if its diagonal BDmeasures 18 cm.
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Perimeter of rhombus P = 4(length of side s) = 60 cm. Length of side s = 15 cm. The length of side s = hypotenuse h of right-triangle with half the lengths of the diagonals (d1/2) and (d2/2) at right angles to each other. h^2 = (d1/2)^2 + (d2/2)^2 => 15^2 = (16/2)^2 + (d2/2)^2 => (d2/2)^2 = 15^2 - 8^2 = 161. d2 = 2 sqrt(161). Area of rhombus = (d1)(d2)/2 = (16)(2 sqrt(161)/2 = 32 sqrt(161)/2 = 16 sqrt(161) = 203.02 cm^2.
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