Question

The perimeter of a rhombus ABCD is 80 cm .find the area of Rhombus if its diagonal BD measures 12 CM.​

Answer 1

Answer:

Step-by-step explanation:

228.95

Answer 2

Answer:

Perimeter of rhombus=80cm

So, Side of rhombus=20cm

Since, perimeter is the sum of all Sides

Diagonals of rhombus are perpendicular bisectors of each other.... So, by Pythagoras at center(let, O) we get...

AB^2=AO^2+BO^2

20^2=6^2+BO^2

BO^2=2√91

So, d2=4√91

Now, area of rhombus = 1/2*d1*d2 = 1/2*12*4√91 = 24√91

Area of rhombus is 24√91