The perimeter of a rhombus ABCD is 80 cm. Find the area of rhombus if its diagonal BD measures 12 cm.
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Answer:
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Step-by-step explanation:
Given,
Diagonal BD of rhombus = 12cm
Perimeter of rhombus = 40cm
4s = 40
s = 40/4
s = 10cm
Now,
Divide the rhombus into four right angled triangles.
Such that, every triangle has a hypotrneuse of 10cm
12/2 = 6cm
Using pythagorus therom :
= √10² - 6²
= 8cm
Now,
8+8= 16cm (sum of the bases of two triangles = measure of d1)
Area of rhombus = 1/2 × d1 × d2
= 1/2 × 16 × 12
= 96cm²
Therefore, diagonal AC = 16cm and the area of rhombus = 96cm²
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