The perimeter of a rhombus is 100cm and one of the diagonal is 40cm then find the length of the other diagonal
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perimeter
4a=100
a=100/4
a=25
side of rhombus=25cm
one diagonal=40cm
another=?
let the diagonals intersect each other at point o
bo=20cm ao=20cm
now in triangle aob
ab=25,ob=20 and ao=?
by pgt
625=ao2+400
225=ao2
ao=15cm
d2=ao+ochttps://hi-static.z-
d2=30cm
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