the perimeter of a rhombus is 120 km and one of its diagonal is 40 cm. fFnd the area of the Rhombus
suraniparvin:
Is perimeter in km
yeah
diagonal is in cm but perimeter is in km right?
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Perimeter of the rhombus= 120km
By formula, perimeter of rhombus=4a (a=length of one side of rhombus)
By the problem,
4a=120
a=30
Length of each side of the rhombus, a=30km
So we know that all the sides of rhombus have equal length.
Again, we know that diagonals of a rhombus bisect each other perpendicularly.
Given, length of one diagonal= 40cm= 0.00040km
Consider the rhombus as ABCD.
One diagonal is AC and another is BD.
Say AC=0.00040km.
Let the diagonals bisect each other at P.
So AP=0.00020KM
In triangle APD,
Angle APD=90 degrees
DP^2=AP^2+AD^2
DP^2= 0.00020*0.00020+30*30=4*10^-8+900= 900KM
DP=30KM
BD=2*30=60KM
Please tell me if there are any mistakes but I'm pretty sure this is the process. Please check the calculations
By formula, perimeter of rhombus=4a (a=length of one side of rhombus)
By the problem,
4a=120
a=30
Length of each side of the rhombus, a=30km
So we know that all the sides of rhombus have equal length.
Again, we know that diagonals of a rhombus bisect each other perpendicularly.
Given, length of one diagonal= 40cm= 0.00040km
Consider the rhombus as ABCD.
One diagonal is AC and another is BD.
Say AC=0.00040km.
Let the diagonals bisect each other at P.
So AP=0.00020KM
In triangle APD,
Angle APD=90 degrees
DP^2=AP^2+AD^2
DP^2= 0.00020*0.00020+30*30=4*10^-8+900= 900KM
DP=30KM
BD=2*30=60KM
Please tell me if there are any mistakes but I'm pretty sure this is the process. Please check the calculations
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