Question

The perimeter of a rhombus is 146 m and one of its diagonals is 48 m, the other diagonal is

Answer 1

Answer:

Perimeter of rhombus =146m

Let each side of rhombus be a

So, Perimeter =4a

4a =146

a=36.5

Now, As diagonals bisect each other

let AC be 48m and diagonals bisect at O(Refer to attachment)

AO=OC= 24

AB= 36.5

In ∆AOB

So, OB = √[(AB)^2-AO^2]

OB = √(36.5)^2 - (24)^2]

OB = √1332.25- 576

=√756.25

=27.5

So other diagonal DB = 2×OB

=2× 27.5

= 55 m

#answerwithquality #BAL

Answer 2

Answer:

Rhombus

Solve for diagonal

p=55m

q Diagonal

48

m

P Perimeter

146

m