the perimeter of a rhombus is 160 cm and one diagonal is 10 cm long the length of other diagonal is
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Step-by-step explanation:
According to question perimeter of the rhombus=160cm
one diagonal=10cm
2×√{(40)²-(10/2)²
2×√(160-25)
6√15 should be the answer
We know that
perimeter of the rhombus =4a
4a=160
a=160/4=40
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