Question

The perimeter of a rhombus is 160 cm and one of its diagonal is 40 cm find area

Answer 1

Answer:

600 sq. cm

Step-by-step explanation:

taking square root both sides

area=

• 1/2*40*30
• 1200/2=600 sq. cm

Answer 2

Answer:

800√3 sq. cm

Step-by-step explanation:

let's In in rhombus ABCD perimeter is equal to 160 cm and diagonal is equals to what is 40 cm

perimeter= 4 ×sides

160= 4 ×sides

160/4=sides

Therefore side of rhombus =40cm

in ∆COD

CO=SO=1/2

AC=1/2×40=20

angle COD=90°

CD=40cn

CD²=OC²+OD²

1600=400+OD²

OD²=1200

OD=√400×3

OD=20√3

therefore BD =2×OD

=2×20√3

=40√3

Area of rhombus=1/2×d1×d2

1/2×40×40√3

800√3sq. cm