The perimeter of a rhombus is 20 cm and one of its diagonals is 6 cm long. Find the length of the other diagonal.
Answers
Answered by
137
let a be the side of rhombus
perimeter of rhombus= 20cm
4a =20
a = 5
diagonals of rhombus bisect each other at 90
hypo.²=height²+base²
25=9+base²
4= base
second diagonal is 4+4=8cm
perimeter of rhombus= 20cm
4a =20
a = 5
diagonals of rhombus bisect each other at 90
hypo.²=height²+base²
25=9+base²
4= base
second diagonal is 4+4=8cm
Answered by
49
Answer:
8 cm
Step-by-step explanation:
let the side of rhombus be 'a'cm and it is give. that perimeter is 20 CM hence the side will be:-
4a=20cm
a=5cm
And we know that diagonals of rhombus bisect each other at 90° and one of its diagonal is 6 CM let's find other using Pythagoras theorum
hypoteneus= 5cm, one side=3cm(as diagonals bisect each other) and other side be 'a' then
-> Hypo²=per²+base²
-> 5²=3²+a²
->25=9+a²
-> a²=16
-> a=4cm
and finally other diagonal =4+4=8cm
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