the perimeter of a rhombus is 20 cm and one of its diagonals main measures 8 centimetre find the other diagonal and area of the Rhombus
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Given perime
ter of rhombus =20cm
one diagonal (d1)=8cm
perimeter of rhombus =20cm
4a =20
a=5 cm
d1=8cm /2
d1 =4cm
by Pythagoras
(h)^2 = (b)^2 +(p)^2
25-16 =(p)^2
square root of 9 = p
p= 3cm
d2 = 6cm
area = 1/2 × d1×d2
= 1/2 × 8×6
24cm^2
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