Question

. The perimeter of a rhombus is 20 cm. One of its diagonals is 8 cm. Then area of the rhombus is
a. 24 cm2
b. 18 cm2
c. 14 cm2
d. 36 cm2

Answer 1

a) 24cm2
Find the side of rhombus by its perimeter using 4*side
Then one diagonal is given find the other using Pythagoras theorem
Then find the area of rhombus using formula 1/2 * d1* d2

Hope it helps and mark as brainliest

Answer 2

Answer:-

★ According to the question:-

→ Let ABCD be the rectangle.

→ E is the mid-point of the side AB

→F is the mid-point of the side BC

→ G is the mid-point of the side CD

→ H is the mid-point of the side DA

The figure obtained by joining the midpoints E, F, G and H is rhombus.

★ We know that:-

Side of the rectangle AB = diagonal of the rhombus FH = 8cm

★ Similarly,

Side of the rectangle AD = diagonal of the rhombus EG = 6cm

Then,

Area of the rhombus = ½ × EG × FH

= ½ × 6 × 8

= 24 cm²

Hence, option (D) is the correct answer.