Question

the perimeter of a rhombus is 24.4 cm and the length of its one of its one of diagonals is 2.2cm . find the area of rhombus ?​

Answer 1

Answer:

perimeter of a rhombus= 24.4

diagonal of rhombus= 2.2

therefore,

area of rhombus= 24.4/2.2=26.84

Answer 2

Perimeter of the rhombus = 24.4 cm.

Side of the rhombus = 6.1 cm.

Length of it's diagonals = 2.2 cm.

Hence d1 / 2 = 1.1 cm.

Let other diagonal be X cm.

d2/2 = X/2 cm.

By Pythagoras Theorem, { 6.1 } ^2 = {1.1 } ^2 + { X ^2 } / 4

X = 12 cm.

Area of rhombus = d1 • d2 / 2 = 1.1 • 6 = 6.6 square cm.

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