Question

The perimeter of a rhombus is 24 cm. If each of its side is increased by 10 %, then what will be the percentage increase in the perimeter?​

Answer 1

Answer:

Diagonals of a rhombus bisect each other at right angle

And diagonals of a rhombus are given as 24 cm and 10 cm

Since they bisect each other at right angle, we have

Side of a rhombus =

12

2

+5

2

=13

⇒ perimeter =4×13=52 cm

Mark me as brainliest