Question

The perimeter of a rhombus is 260 cm and height is 10 cm. If one diagonal is 0.25, find the length of other diagonal in meters​

Answer 1

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \boxed{\boxed { \huge \mathcal\red{ solution}}}}$

$\huge \star$For the Rhombus:

$\implies$perimeter(p)= 260 cm

Now we know for a rhombus

$\implies \bf \boxed{\red{perimeter (p)=4\times side}}$

$\implies \bf base=\frac{perimeter}{4} \\ \implies \bf base=\frac{\cancel{260}}{4}\\ \implies \bf base=65 \:cm$

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$\huge \star$Given:

$\implies$base(b)=10 cm

$\implies$height(h)=10 cm

$\implies diagonal(d_1)=0.25cm=25 cm$

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$\bf\star \:Rhombus \;with\: diagonal \:\blue{\bf d_1}\: and\: \blue{d_2}\:$

$\implies\boxed{ \red{Area=d_1\times d_2}}$

$\bf\star \:Rhombus \;with\: base\blue{\bf \:b}\: and \:height\:\blue{\bf h\:}$

$\implies\boxed{ \red{Area=b\times h}}$

$\therefore \bf Area=d_1\times d_2=b\times h\\ \implies \bf d_2={b\times h}{d_1}\\ now,\: putting \:the \:values\\ \implies \bf d_2={65\times 10}{25}\\ \implies \boxed{\red{ d_2=26 cm}}$

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$\underline{ \huge\mathfrak{hope \: this \: helps \: you}}$

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