Question

the perimeter of a rhombus is 260 cm and height is 10 cm if one diagonal is 0.25 M, find the length of other diagonals in metres

Answer 1

Suppose a be the length of each side of rhombus.
So, its perimeter = 4a = 260 cm
⇒a = 2604 = 65 cm = 0.65 m
Height of rhombus = 10 cm = 0.1 m
So, area of rhombus = base × height = 0.65 ×0.1 = 0.0650 m2
Now, length of one diagonal of rhombus = 0.25 m
Suppose length of other diagonal is d 
And we know that area of rhombus when length of diagonals are given = 12 (product of length of two diagonals)
So, we have;
12(d×0.25) = 0.065⇒d×0.25 = 0.065×2⇒d =  0.065×20.25 = 0.52
Therefore, length of other diagonal is 0.52 m.

Hope it helps.


Please mark it as brainliest.

Answer 2

The length of other diagonals is 0.52 meters.

Step-by-step explanation:

Given information:

Perimeter of a rhombus = 260 cm

Height = 10 cm

One diagonal = 0.25 m

We know that

1 m = 100 cm

Using this conversion we get

Perimeter of a rhombus = 2.6 m

Height = 0.1 m

All sides of a rhombus are congruent. So, the measure of each side is

$\frac{2.6}{4}=0.65$

Let the length of second measure is x meter.

Area of a rhombus is

$Area= base\times height$

$Area= 0.65\times 0.1=0.065$           .... (1)

$Area= \frac{1}{2}(d_1\times d_2)$

where, d₁ and d₂ are diagonals.

$Area= \frac{1}{2}(0.25\times x)$

$Area= 0.125x$             .... (2)

On equating (1) and (2), we get

$0.125x=0.065$

Divide both sides by 0.125

$x=\frac{0.065}{0.125}$

$x=0.52$

Therefore, the length of other diagonals is 0.52 meters.

#Learn more

The perimeter of a rhombus is 260 cm and height is 10 cm if one diagonal is 0.25 M, find the length of other diagonals in metres

https://brainly.in/question/2352654

https://brainly.in/question/7326852