Math, asked by dprerao, 11 months ago

the perimeter of a rhombus is 328cm . one of its diagnol is 160cm . find the lenght of the other diagnol and the area of the rombhus

Answers

Answered by krishanamandal110
3

Answer:

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given

328 = 4 × side =>side = 328/4 = 82.We may use Pythagoras theorem the calculate half of the other diagonal.Then,our hypotenuse = 82 and perpendicular = 160/2=80.

82^2 - 80^2 = half of the other diagonal^2

=> √324 = half of the other diagonal.

half of the other diagonal = 18

the whole diagonal = 2 times its half

=>2 × 18 = 36

We know that diagonal × the other diagonal / 2 = area

36 × 160 /2 = 36 × 80 = 2,880 cm^2 is your answer.

Answered by Anonymous
2

SOLUTION:

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given328 = 4 × side =>side = 328/4 = 82.We may use Pythagoras theorem the calculate half of the other diagonal.Then,our hypotenuse = 82 and perpendicular = 160/2=80.

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given328 = 4 × side =>side = 328/4 = 82.We may use Pythagoras theorem the calculate half of the other diagonal.Then,our hypotenuse = 82 and perpendicular = 160/2=80.82^2 - 80^2 = half of the other diagonal^2

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given328 = 4 × side =>side = 328/4 = 82.We may use Pythagoras theorem the calculate half of the other diagonal.Then,our hypotenuse = 82 and perpendicular = 160/2=80.82^2 - 80^2 = half of the other diagonal^2=> √324 = half of the other diagonal.

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given328 = 4 × side =>side = 328/4 = 82.We may use Pythagoras theorem the calculate half of the other diagonal.Then,our hypotenuse = 82 and perpendicular = 160/2=80.82^2 - 80^2 = half of the other diagonal^2=> √324 = half of the other diagonal.half of the other diagonal = 18

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given328 = 4 × side =>side = 328/4 = 82.We may use Pythagoras theorem the calculate half of the other diagonal.Then,our hypotenuse = 82 and perpendicular = 160/2=80.82^2 - 80^2 = half of the other diagonal^2=> √324 = half of the other diagonal.half of the other diagonal = 18the whole diagonal = 2 times its half

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given328 = 4 × side =>side = 328/4 = 82.We may use Pythagoras theorem the calculate half of the other diagonal.Then,our hypotenuse = 82 and perpendicular = 160/2=80.82^2 - 80^2 = half of the other diagonal^2=> √324 = half of the other diagonal.half of the other diagonal = 18the whole diagonal = 2 times its half=>2 × 18 = 36

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given328 = 4 × side =>side = 328/4 = 82.We may use Pythagoras theorem the calculate half of the other diagonal.Then,our hypotenuse = 82 and perpendicular = 160/2=80.82^2 - 80^2 = half of the other diagonal^2=> √324 = half of the other diagonal.half of the other diagonal = 18the whole diagonal = 2 times its half=>2 × 18 = 36We know that diagonal × the other diagonal / 2 = area

Since all sides are equal in a rhombus then it's perimeter = 4 × side,now the perimeter is given328 = 4 × side =>side = 328/4 = 82.We may use Pythagoras theorem the calculate half of the other diagonal.Then,our hypotenuse = 82 and perpendicular = 160/2=80.82^2 - 80^2 = half of the other diagonal^2=> √324 = half of the other diagonal.half of the other diagonal = 18the whole diagonal = 2 times its half=>2 × 18 = 36We know that diagonal × the other diagonal / 2 = area36 × 160 /2 = 36 × 80 = 2,880 cm^2 is your answer.

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