The perimeter of a rhombus is 40 cm and its diagonal is 12 cm. Find the length of other diagonal
Also, find the area of the rhombus.
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Let ABCD is a rhombus whose each side is x cm., diagonal AC =12cm. Other diagonal BD meets AC at point O.
x=p/4=40/4=10cm.
In right angled triangle AOB
OA^2+OB^2= AB^2
(AC/2)^2+(BD/2)^2=(x)^2
(12/2)^2+(BD)^2=(10)^2
(BD^2)/4=100–36=64
BD^2=256
BD=16 cm. , Answer
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