Question

the perimeter of a rhombus is 40 cm and the length of one of its diagonal is 16 cm find its area​

Answer 1

Answer:

Answer :

First of all we will find length of side of rhombus by using formula

the perimeter of rhombus = 4 * sides

40 = 4 * sides

10 cm = side of rhombus

now we know that diagonal of rhombus are perpendicular bisectors of each other hence by using Pythagoras theorem

(10)squared = (8)squared + (x)squared

6 cm = x

12 cm is length of other diagonal .....(6 * 2)=12 cm

Now area of rhombus = 1/2 * product of length of diagonals

= 1/2 * 16 *12

=96 sq.cm

length of other diagonal is 12 cm and area of rhombus is 96 sq.cm