Question

the perimeter of a rhombus is 40 cm. if one of its diagonals is 16 cm, find the other diagonal.

Answer 1

Answer:

Step-by-step explanation:

Perimeter = 40 cm

Side = 40 / 4 = 10 cm

D1 = 16 cm

D2 = 2 × sqrt [side^2 - (d1/2)^2]

= 2 × sqrt [ (10)^2 - (16/2)^2]

= 2 × sqrt [ 100 - 64]

= 2 × sqrt (36)

= 12

Area = 1/2 D1 × D2

= 12 × 16 / 2

= 6 × 16

= 96 cm^2

Answer 2

Answer:

First of all we will find length of side of rhombus by using formula

the perimeter of rhombus = 4 * sides

40 = 4 * sides

10 cm = side of rhombus

now we know that diagonal of rhombus are perpendicular bisectors of each other hence by using Pythagoras theorem

(10)squared = (8)squared + (x)squared

6 cm = x

12 cm is length of other diagonal .....(6^2)=12 cm