the perimeter of a rhombus is 40 cm. if one of the diagonals is 16 cm then find the length of the other diagonal.
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Perimeter of rhombus = 40 cm
Diagonal 1 = 16 cm
Diagonal 2 = x cm
Perimeter of rhombus = 2√p²+q²
40 = 2√16²+x²
20 = √256+ x²
20² = 256 + x²
400 = 256 + x²
400- 256 = x²
144 = x²
x = √144
x = √12x12
x=12 cm
the length of the other diagonal is 12cm
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