The Perimeter of a rhombus is 40 cm. If the length of one of its diagonals is 12 cm, what is the area of the Rhombus?
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Answer:
96cm
Step-by-step explanation:
A=pq
2
P=4a
a=p2+q2
2
Solving forA
A=1
4pP2﹣4p2=1
4·12·402﹣4·122=96cm²
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