the perimeter of a rhombus is 40cm and the length of one diagonal is 16cm find the length of the other diagon
Answers
40=4*s
side=10cm
now, area of rhombus=side^2=10^2=100cm^2.
,from the question,
area of rhombus=1/2*dialgonal1*diagonal2=1/2*16*d2=
area of rhombus=1/2*16*d2
100=8*d2
hence ,d2=100/8=12.5cm...mark brainlist or thanks...
Answer:
AnSwer -:
Length of Diagonal 2 = 8cm
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Explanation-:
Area of the Rhombus -:
“A = 1/2 x d1 x d2”
A = Area
D1 = Diagonal 1
D2 = Diagonal 2
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Given,
Area of Rhombus-: 16 cm^2
Length of Diagonal 1 = 4 cm
To find,
Length of diagonal 2
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Formula of Area of Rhombus-:
Area of the Rhombus -:
“A = 1/2 x d1 x d2”
A = Area = 16 cm^2
D1 = Diagonal 1 = 4 cm
D2 = Diagonal 2 = ??
Then ,
1/2 x 4 x D2 = 16 cm^2
2 x d2 = 16 cm^2
D2 = 16/2
D2 = 8
Hence ,
Length of Diagonal 2 = 8cm
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Rhombus-: A Rhombus is a flat shape
with 4 equal straight sides. A rhombus
looks like a diamond. All sides have
equal length.
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Step-by-step explanation:
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