the perimeter of a rhombus is 40cm .if one diagonal is 16 cm find its another diagonal
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0
perimeter of rhombus=4a
=4×40
=160cm²
the other diagonal=2√160²-(16/2)²
=2√3200-64
=2×√3136
=2×56
=112cm ans
=4×40
=160cm²
the other diagonal=2√160²-(16/2)²
=2√3200-64
=2×√3136
=2×56
=112cm ans
Answered by
6
Answer:
• Length of other diagonal = 12 cm.
Step by step explanation:
[ Refer the attachment for figure. ]
Perimeter of Rhombus = 40 cm.
» Side = 1/4 × 40 = 10 cm.
One diagonal = 16 cm.
Diagonals of Rhombus bisect each other at right angles.
Now,
OB = √ (AB² - OA²)
= √ ( 10² - 8² )
= √ ( 100 - 64 )
= √ 36
= 6 cm.
Thus, Diagonal BD = 6 × 2 = 12 cm.
Final answer:
Length of other diagonal = 12 cm.
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