Question

The perimeter of a rhombus is 40cm. If one of its diagonals is 16cm, find the area of the rhombus

Answer 1

Hey mate....

Here’s ur answer... :)

the perimeter of rhombus = 4 * sides

= 40/4 = 10 cm...

10 cm = side of rhombus....

diagonal of rhombus are perpendicular bisectors of each other.....so by using Pythagoras theorem

(10)^2 = (8)^2+ (x)^2

6 cm = x

12 cm is length of other diagonal .....(6 * 2)=12 cm

Now area of rhombus = 1/2 * d1 * d2

= 1/2 * 16 *12

=96 sq.cm

So the area of rhombus is 96 sq.cm....

Hope it helps.... :)