The perimeter of a rhombus is 40cm. If the length of one of its diagonals be 12m,then the length of the other diagonal is
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Perimeter of rhombus is given by sum of all sides
Since the sides are all of same length, let’s call them x
So 4x = 40
X= 10 cm . Is each side length.
Now to find the other diagonal, you use the Pythagoras theorem and then multiply the answer by 2 to get the entire length.
We know the hypotenuse is now 10 cm. One of the sides are 12/2 = 6 cm. So substitute—-
10^2 = 6^2 + x^2
100= 36+ x^2
X^2 = 64
X= 8
8x2=16. Now you get it right?! Pls mark as brainliest !!!!!
Since the sides are all of same length, let’s call them x
So 4x = 40
X= 10 cm . Is each side length.
Now to find the other diagonal, you use the Pythagoras theorem and then multiply the answer by 2 to get the entire length.
We know the hypotenuse is now 10 cm. One of the sides are 12/2 = 6 cm. So substitute—-
10^2 = 6^2 + x^2
100= 36+ x^2
X^2 = 64
X= 8
8x2=16. Now you get it right?! Pls mark as brainliest !!!!!
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