The perimeter of a rhombus is 52 cm and one of its diagonals is 24 cm. find its area.
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perimeter of the Rhombus is equal to 52 centimetre
P=4*side
52=4*side
side=13cm.
to find second diagonal of the Rhombus
by applying Pythagoras theorem
we know aside and diagnol
(h)^2= (b)^2+ (p)^2
(13)^2=(12^2)+(b)^2
(b)^2=169-144
(b)^2=√25
base 5cm.
full diagnol =5+5=10cm.
now we have both are diagnols.
area=1/2d1*d*2
area=1/2*10*24
area=120cm^2 answer.
P=4*side
52=4*side
side=13cm.
to find second diagonal of the Rhombus
by applying Pythagoras theorem
we know aside and diagnol
(h)^2= (b)^2+ (p)^2
(13)^2=(12^2)+(b)^2
(b)^2=169-144
(b)^2=√25
base 5cm.
full diagnol =5+5=10cm.
now we have both are diagnols.
area=1/2d1*d*2
area=1/2*10*24
area=120cm^2 answer.
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