The perimeter of a rhombus is 52 cm and one of its diagonals is 10 cm. Find the length of the other diagonal and the area of the rhombus.
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Answer:
We have,
Parameter of a rhombus=52cm.
Its diagonal=10cm.
Let the length of the other diagonal=xcm
Area of rhombus =?
Now,
Parameter of rhombus =4×side
52=4×side
⇒side=13cm.
Therefore, each side of rhombus =13cm.
Then, the length of other diagonal=2132−(210)2
x=2169−25
x=2×144
x=2×12
x=24cm.
We know that,
Area of rhombus=21× product of diagonals
=21×10×24
=5×24
=120cm.2
Hence, this is the answer
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