the perimeter of a rhombus is 52 cm and one of the diagonal is 24cm find the area of the rhombus.
Answers
Answered by
5
Diagonals of a rhombus bisect each other at 90 degrees
Half of each diagonal and one side would for a right angled triangle with the side of the rhombus as the hypotenuse
One side is 52cm/4 = 13cm
Half of given diagonal is 5cm
Half of the other diagonal is √(13² - 5²) = 12cm
The other diagonal is 12cm×2 = 24cm
Area of rhombus = half product of diagonals = (1/2) × 10cm × 24cm = 120cm²
Similar questions