The perimeter of a rhombus is 52cm & one diagonal is 10 cm long then the area of the rhombus is
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Perimeter of a rhombus = perimeter of a square =4×side =52cm
=4×side = 52
Side=52÷4= 13 cm
Note: We know that the diagonals of a rhombus bisect each other at right angles.
In right triangle ABC:
OA = ½×AC = ½×10 =5 cm
OB= √AB²-OA²
OB=√(13)²-(5)²
OB=√169-25
OB=√144= 12 cm
BD= ( 2×OB) cm = (2×12) cm = 24 cm
Area of a rhombus= ½× product of its diagonals
= ½× AC×BD = ½×10× 12= 60 cm²
=4×side = 52
Side=52÷4= 13 cm
Note: We know that the diagonals of a rhombus bisect each other at right angles.
In right triangle ABC:
OA = ½×AC = ½×10 =5 cm
OB= √AB²-OA²
OB=√(13)²-(5)²
OB=√169-25
OB=√144= 12 cm
BD= ( 2×OB) cm = (2×12) cm = 24 cm
Area of a rhombus= ½× product of its diagonals
= ½× AC×BD = ½×10× 12= 60 cm²
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