The perimeter of a rhombus is 52cm. If one of its diagonal is 24cm long,find the length of the other diagonal and the area of the rhombus
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The perimeter of a rhombus is 52cm.
each side=52/4=13cm
one of the diagonal=24cm=d1
from the figure
from ∆BOC
OC=24/2=12cm; BC=13cm
BC^2=BO^2+OC^2
13^2 =BO^2+12^2
169=BO^2+144
BO^2=169-144=25
BO=√25=5cm. d2=5+5=10cm(BD=BO+OD)
The Other diagonal of rhombus is 10 cm
area of Rhombus=1/2 d1d2
=1/2×24×10
=120cm
each side=52/4=13cm
one of the diagonal=24cm=d1
from the figure
from ∆BOC
OC=24/2=12cm; BC=13cm
BC^2=BO^2+OC^2
13^2 =BO^2+12^2
169=BO^2+144
BO^2=169-144=25
BO=√25=5cm. d2=5+5=10cm(BD=BO+OD)
The Other diagonal of rhombus is 10 cm
area of Rhombus=1/2 d1d2
=1/2×24×10
=120cm
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