Question

The perimeter of a rhombus is 60cm.If one diagonal is 24cm,find the length of the other diagonal
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Answer 1

HeYa

Here is your Answer:

♣ QUADRILATERALS ♣

Given.

Perimeter = 60 cm

4a = 60

a = 60/4 = 15 cm

So, Side = 15 cm

We know,

Pythagorean Theorem,

H² = B² + P²

(AB)² =  (OA)² + (OB)²

(15)² = (OA)² + (12)²

225 = (OA)² + 144

225 - 144 = (OA)²

81 = (OA)²

9 = OA

Then AC = 2 x 9 = 18 cm

Now, Area = 1/2 * product of its diagonals

                = 1/2 * 24 * 18

                = 216 cm² 

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Answer 2

Answer:

It is a Quadilateral so

Step-by-step explanation:

WE NEED TO USE THE PYTHOGORAS THEORAM

Given.

Perimeter = 60 cm

4a = 60

a = 60/4 = 15 cm

So, Side = 15 cm

We know,

Pythagorean Theorem,

H² = B² + P²

(H)² =  (B)² + (P)²

(15)² = (B)² + (12)²

225 = (B)² + 144

225 - 144 = (B)²

81 = (B)²

9 = B

Then AC = 2 x 9 = 18 cm