Question

The perimeter of a rhombus is equal to 120 m and one of the diagonals measures 50m. Find the length of the other diagonal.

Answer 1

Answer:

Step-by-step explanation:

Let the side of the rhombus =x

4x=120

x=30m

Diagonal =50m

Let Half of diagonal=y=25m

Let half of the 2nd diagonal=z

By Pythagoras theorem

z^2=x^2-y^2

=30^2-25^2

225

z=15

The 2nd diagonal =2*15=30m

Answer 2

Answer:

2(5√11) = 10√11

Step-by-step explanation:

perimeter of rhombus = ( 4 × side )

120 = 4s

s = 30

the diagonals of a rhombus intersect at 90° and bisect each other

therefore the half of the other diagonal will be

(5√11) by Pythagoras theorem

and its total length will be 2(5√11) = 10√11