The perimeter of a rhombus is equal to 120 m and one of the diagonals measures 48 m. Find the length of the other diagonal.
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I hope this will help you sreelover,
As the diagonals of rhombus bisects eac h other by 90°
Side are equal in rhombus
Perimeter =4*side
120=4*side
120/4=side
30=side
Then by Pythagoras theorem,
Side²=(half of first diagonal)²+ (half of other diagonal)²
30²=24²+half of other diagonal²
900-576
324= half of other diagonal²
√324=18= half of other diagonal
Other diagonal =18+18=36cm
As the diagonals of rhombus bisects eac h other by 90°
Side are equal in rhombus
Perimeter =4*side
120=4*side
120/4=side
30=side
Then by Pythagoras theorem,
Side²=(half of first diagonal)²+ (half of other diagonal)²
30²=24²+half of other diagonal²
900-576
324= half of other diagonal²
√324=18= half of other diagonal
Other diagonal =18+18=36cm
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this is required answer
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