Question

The perimeter of a rhombus whose
diagonals are 16 cm and 12 cm long is:​

Answer 1

Answer:

40cm..........................

Answer 2

Step-by-step explanation:

we know that diagonals of rhombus bisect each other at 90°

so.. if they bisect then.. they will be 8cm and 6cm

and they form a traingle with one side of rhombus ..

so.. by phythagoras theorem

side² = diagonal 1 ² + diagonal 2 ²

side ² = 8²+6²

side² = 64+36

side = √100 = 10cm

so... perimeter= 4 *side

4*10 = 40cm

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